what is the value of Erms?show it by full process.
Asked by joshika saraf | 9th Sep, 2011, 12:00: AM
Derivation of root mean square voltage formula:
At any time, t, the voltage is given by
E = Eo sin?t
Squaring
E2 = Eo2 sin2?t
But, from trigonometry, sin2? = ½(1 - cos2?)
Giving
E2 = ½Eo2 - ½ Eo2 cos 2?t
But the average of cos 2?t over a complete cycle is zero. The average square of the voltage over a whole cycle will be E2 = ½Eo2.
Thus, the ROOT MEAN SQUARE VOLTAGE will be ERMS = Eo/?2 = 0.707Eo
A similar argument will show that the ROOT MEAN SQUARE CURRENT will be Io/?2 = 0.707Io.
Derivation of root mean square voltage formula:
At any time, t, the voltage is given by
E = Eo sin?t
Squaring
E2 = Eo2 sin2?t
But, from trigonometry, sin2? = ½(1 - cos2?)
Giving
E2 = ½Eo2 - ½ Eo2 cos 2?t
But the average of cos 2?t over a complete cycle is zero. The average square of the voltage over a whole cycle will be E2 = ½Eo2.
Thus, the ROOT MEAN SQUARE VOLTAGE will be ERMS = Eo/?2 = 0.707Eo
A similar argument will show that the ROOT MEAN SQUARE CURRENT will be Io/?2 = 0.707Io.
Answered by | 10th Sep, 2011, 02:08: PM
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