what is the stopping potential ofa photocell, in which electrons with a maximum kinetic energy of 6eV are emitted ?

Asked by aruni_maiyer | 3rd Mar, 2012, 03:54: PM

Expert Answer:

Stopping potential = (KE)max/e = 6eV/e = 6 V

Answered by  | 3rd Mar, 2012, 10:42: PM

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