what is the smallest no. which when divided by 35,65 and 104 leaves remainder 5 in each case? please explain the solution

Asked by  | 6th May, 2013, 06:27: PM

Expert Answer:

35 = 5 x 7
65 = 5 x 13
104 = 2 x 2 x 2 x 13
 
LCM of 35, 65, 104 = 3640
 
Thus, the smallest no. which when divided by 35,65 and 104 leaves remainder 5 in each case
= 3640 + 7 = 3647

Answered by  | 7th May, 2013, 10:13: AM

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