CBSE Class 10 Answered
what is the smallest no. which when divided by 35,65 and 104 leaves remainder 5 in each case?
please explain the solution
Asked by | 06 May, 2013, 06:27: PM
Expert Answer
35 = 5 x 7
65 = 5 x 13
104 = 2 x 2 x 2 x 13
LCM of 35, 65, 104 = 3640
Thus, the smallest no. which when divided by 35,65 and 104 leaves remainder 5 in each case
= 3640 + 7 = 3647
Answered by | 07 May, 2013, 10:13: AM
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