WHAT IS THE REMAINDER WHEN 5Xcube-7Xsquare+3X+13 IS DIVIDED BE X/2+1

Asked by Keerthi | 8th Jun, 2017, 08:20: PM

Expert Answer:

begin mathsize 16px style By space remainder space theorem comma space required space remainder space is space equal space to space straight p open parentheses negative 2 close parentheses comma space space space space space open square brackets straight x over 2 plus 1 equals 0 rightwards double arrow straight x over 2 equals negative 1 rightwards double arrow straight x equals negative 2 close square brackets
Now comma space straight p left parenthesis straight x right parenthesis equals 5 straight x cubed minus 7 straight x squared plus 3 straight x plus 13
rightwards double arrow straight p left parenthesis negative 2 right parenthesis equals 5 left parenthesis negative 2 right parenthesis cubed minus 7 left parenthesis negative 2 right parenthesis squared plus 3 left parenthesis negative 2 right parenthesis plus 13
space space space space space space space space space space space space space space space space equals 5 left parenthesis negative 8 right parenthesis minus 7 left parenthesis 4 right parenthesis minus 6 plus 13 space
space space space space space space space space space space space space space space space space equals negative 40 minus 28 minus 6 plus 13
space space space space space space space space space space space space space space space space equals negative 61
Hence comma space required space remainder space is space minus 61. end style

Answered by Rashmi Khot | 9th Jun, 2017, 09:53: AM

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