What is the probability of having 53 Thursdays in a non-leap year?
Asked by Topperlearning User | 27th Jul, 2017, 04:29: PM
In a non- leap year, there are 365 days, i.e. 52 weeks.
52 weeks = 364 days
1year = 52weeks and 1 day
This extra one day can be mon,tue,wed,thu,fri,sat,or sun.
Total number of outcomes = 7
Number of favourable outcomes =1
P(having 53 Thursdays) =
Answered by | 27th Jul, 2017, 06:29: PM
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