what is the probability of having 53 Sundays in a leap year?
Asked by | 30th Jan, 2012, 08:40: PM
A leap year has 366 days, i.e. 52 weeks & 2 days
52 weeks will have 52 Sundays.
The other two days can be either one of the following pairs:
(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday) and (Saturday, Sunday)
Out of these pairs, 2 of them includes a Sunday.
Therefore, the required probability of having 53 Sundays = 2 / 7
Answered by | 30th Jan, 2012, 10:06: PM
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