what is the oxidation state of K in KO2?
 

Asked by rajenderdagar123 | 14th Feb, 2017, 09:15: PM

Expert Answer:

The oxidation state of each oxygen atom is -1/2 since it is a superoxide ion.
Let the oxidation state of K be x.
x + 2(-1/2) = 0
2x-2 = 0
2x=2
x=+1

Answered by Vaibhav Chavan | 15th Feb, 2017, 11:31: AM