what is the maximum value of??

Asked by kanishkaaggarwal | 6th Jan, 2010, 04:57: PM

Expert Answer:

f(x) = (1/2)y where y = x2 - 3x +2

Taking log on both sides,

ln f(x) = (x2 - 3x +2) ln (1/2)

Differentiating on both sides,

(1/f(x)) df(x)/dx = (2x -3) ln (1/2)

For the maximum value of the function,

df(x)/dx = 0

df(x)/dx = 0

(2x-3) = 0

x = 3/2

y = -1/4

Hence f(3/2) = (1/2)-1/4 = (2)1/4

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Answered by  | 7th Jan, 2010, 12:14: AM

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