What is the mass of calcium carbonate precipitated when calcium chloride solution is added to a solution containing 21.2g of sodium carbonate?
RMM of sodium carbonate = 106
RMM of calcium carbonate = 100
Asked by ben_kpg | 20th Jun, 2019, 04:12: PM
Expert Answer:
NaCO3 + CaCl2 → NaCl + CaCO3
21.2g
The relative molar mass of NaCO3 is 106 g per mole.
This means mass of 1 mole of NaCO3 = 106 g
1 mole of NaCO3 liberates 1 mole of CaCO3
Therefore 0.2 mole of NaCO3 liberates 0.2 mole of CaCO3
= 100×0.2 .......................... (relative molar mass of CaCO3=100)
= 20g
NaCO3 + CaCl2 → NaCl + CaCO3
The relative molar mass of NaCO3 is 106 g per mole.
This means mass of 1 mole of NaCO3 = 106 g
Answered by Ramandeep | 21st Jun, 2019, 02:07: PM
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