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ICSE Class 10 Answered

What is the mass of calcium carbonate precipitated when calcium chloride solution is added to a solution containing 21.2g of sodium carbonate? RMM of sodium carbonate = 106 RMM of calcium carbonate = 100
Asked by ben_kpg | 20 Jun, 2019, 04:12: PM
answered-by-expert Expert Answer

NaCO3 + CaCl2 →  NaCl + CaCO3

21.2g
 
The relative molar mass of NaCO3  is 106 g per mole.
This means mass of 1 mole of NaCO3 = 106 g
 
Number space of space moles space equals fraction numerator Given space mass over denominator Mola space mass end fraction space equals space fraction numerator 21.2 over denominator 106 end fraction space equals space 0.2 space mol

 
1 mole of NaCO3 liberates 1 mole of CaCO3
Therefore 0.2 mole of NaCO3 liberates 0.2 mole of CaCO3
= 100×0.2    .......................... (relative molar mass of CaCO3=100)
= 20g
Answered by Ramandeep | 21 Jun, 2019, 02:07: PM

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