CBSE Class 12-science Answered
what is the integration of log(1+x) divided by (1+x2)
Asked by | 16 Jan, 2010, 08:11: PM
Expert Answer
Dear Student log(1+x2)/(1+x2) Put x = tany so, dx = sec2y dy and 1+tan2y =sec2y ==> Integral changes to log (sec2y) dy = 2log sec y Integral log (x) = x ln(x) - x + C. and derivative of secy= secy tan y = 2[ sec y ln(sec y) -sec y + C] / (secy tany) y= arc tan(x)
==>Integral 2 log sec y dy
Regards
Team
Topperlearning
Answered by | 17 Jan, 2010, 11:53: AM
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