what is the force brtween two small charged spheres having charges of 2x10power-7coulomb and 3x10power-7 colomb placed 30cm part in air?

Asked by moinkhan440455 | 6th Apr, 2020, 01:38: PM

Expert Answer:

q1 = 2×10-7 C
q2 = 3×10-7 C
r =30 cm = 0.3 m 
 
By Coulomb's law, 
F space equals space fraction numerator k q subscript 1 q subscript 2 over denominator r squared end fraction
F space equals space fraction numerator q subscript 1 q subscript 2 over denominator 4 πε subscript 0 straight r squared end fraction space equals space fraction numerator 9 cross times 10 to the power of 9 cross times 2 cross times 10 to the power of negative 7 end exponent cross times 3 cross times 10 to the power of negative 7 end exponent over denominator 0.3 squared end fraction
S o l v i n g comma space w e space g e t comma space
F space equals space 6 cross times 10 to the power of negative 3 end exponent space N space space
 
Thus, the force between the two small charged spheres is 6×10-3 N. 

Answered by Shiwani Sawant | 6th Apr, 2020, 01:48: PM

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