What is the distance covered by freely falling body during the first three sec of its motion.(g =10m/s)

 

Distance S covered by freely falling body in first 3 seconds is detrmined from the following relation

 

S = (1/2) g t² = 0.5 × 9.8 × 3 × 3 = 44.1 m

 

where g is acceleration due to gravity and t is time in seconds