What is the distance covered by freely falling body during the first three sec of its motion.(g =10m/s)

 

Asked by harjot.arshleen | 31st Jan, 2021, 03:18: PM

Expert Answer:

Distance S covered by freely falling body in first 3 seconds is detrmined from the following relation
 
S = (1/2) g t2 = 0.5 × 9.8 × 3 × 3 = 44.1 m
 
where g is acceleration due to gravity and t is time in seconds

Answered by Thiyagarajan K | 31st Jan, 2021, 09:39: PM

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