what is the derivation of E=mc^2

Dear student,

 

Delta x = vt

t = 2x/c

Delta x = 2vx/c

P =2 m v

E = PC, P = E/C

xm + xm = 0

(-x+delta x )(m+ delta m)+ (x+delta x)(m- deltam) =0

solving,

delta m = (m/x) (delta x)

delta m = m/x (v2x/c) = P/c

Hence, delta m = E/c^2

E = delta m c^2

E = mc^2

Hope this helps.

Thanking you

Team

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