what is the argument of (-1-iota)

Asked by  | 19th Apr, 2013, 10:15: AM

Expert Answer:

Argument of z = a+ib is equal to tan-1(b/a)
 
Hence, argument of -1-i = tan-1(-1/-1) = pi/4

Answered by  | 19th Apr, 2013, 07:05: PM

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