What is the area of quadrilateralABCD whos sides are 9m,40m,28m,15m?

Asked by jishnu1994 | 25th Dec, 2009, 11:11: PM

Expert Answer:

s = semiperimeter = (9+40+28+15)/2 = 46 m

A = ((s-a)(s-b)(s-c)(s-d)) = (37X6X18X31) = 351.91 m2

Regards,

Team,

TopperLearning.

Answered by  | 26th Dec, 2009, 12:16: AM

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