What is the answer?
Asked by sanabamdiana46 | 13th Nov, 2020, 06:33: PM
Let us assume current I is passing through a wire of hollow cylindrical crosssection with inner radius Ri and outer radius Ro .
By Ampere's law , magnetic field induction B(r) at a radial distance from center of cross section is given as ,
where Ienc is enclosed current with in the circle of radius r drawn with centre as centre of crossection of hollow cylinderical wire .
At a distance r ≤ Ri , enclosed current is zero . Hence Magnetic field is zero
At a distance r such that Ri ≤ r ≤ Ro , enclosed current I enc= current density × crosssection area
Magnetic field B at a distance r such that Ri ≤ r ≤ Ro , is given as
At a distance r such that r > Ro , enclosed current I enc is the total current passing through wire.
Hence magnetic field ar r > Ro
Answered by Thiyagarajan K | 14th Nov, 2020, 11:38: AM
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