What is the amount of magnesium required to form 160 gram of magnesium oxide by burning magnesium in air

Asked by Vinitasonber073 | 21st Sep, 2018, 12:13: PM

Expert Answer:

Given:
 
Mass of magnesium oxide = 160 gm
 
Reaction equation is;
 
space space space space space space 2 Mg space space plus space space straight O subscript 2 space space rightwards arrow space space 2 MgO

space space space 2 space mole space space space space space 1 space mole space space space space 2 space mole

Moles space of space MgO space equals fraction numerator Mass space of space MgO over denominator Molar space mass end fraction

space space space space space space space space space space space space space space space space space space space space space space equals 160 over 40

Moles space of space MgO space equals space 4 space moles

2 space moles space og space MgO space requires space 2 space mole space of space Mg

4 space moles space og space MgO space will space require space space fraction numerator 4 cross times 2 over denominator 2 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 4 space moles space of space Mg
 
4 moles of magnesium is required to form 160 gm of magnesium oxide.
 

Answered by Varsha | 24th Sep, 2018, 06:43: PM