What is net electric field intesity at the centre point of a dipole?

Asked by pragya.sharma.1998 | 23rd May, 2015, 04:36: PM

Expert Answer:

$begin mathsize 14px style 1. space Electric space field space intensity space due space to space straight a space dipole space at space straight a space point space on space its space axis space is space given space by colon straight E equals fraction numerator 1 over denominator 4 πε subscript 0 end fraction fraction numerator 2 pr over denominator open parentheses straight r squared minus straight l squared close parentheses squared end fraction where space straight r space is space the space distance space of space the space point space from space t h e space centre space of space the space dipole. and space 2 space straight l space the space seperation space between space the space two space charges Here space at space the space centre space of space the space dipole comma space straight r equals 0 rightwards double arrow space straight E space equals 0 2. space Electric space intensity space due space to space straight a space dipole space at space straight a space point space in space its space equatorial space position space is space given space by colon straight E equals fraction numerator 1 over denominator 4 πε subscript 0 end fraction straight p over open parentheses straight r squared plus straight l squared close parentheses to the power of begin display style 3 over 2 end style end exponent At space the space centre space of space the space dipole comma space straight r space equals 0 rightwards double arrow space straight E space equals fraction numerator 1 over denominator 4 πε subscript 0 end fraction fraction numerator straight p over denominator open parentheses straight l cubed close parentheses end fraction end style$

Answered by Jyothi Nair | 24th May, 2015, 04:12: PM

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