What is a probability of 53 Sundays in a leap year???
Asked by
| 27th Jul, 2009,
02:50: PM
there are 52 sundays in a non leap year.
so in a leap year the two extra days(366=364+2)
there are seven possibilities for the extra day
i.e. the sample space isS={ mon,-tue, tue-wed...sat- sun,sun-mon} (7 possibilities)..n(S)=7
out of which two cases are fav for the event of having a sunday..n(E)=2
so the prob of there being 53 sundays is
n(E)/n(s)=2/7.
Answered by
| 27th Jul, 2009,
03:38: PM
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