What is a probability of 53 Sundays in a leap year???

Asked by  | 27th Jul, 2009, 02:50: PM

Expert Answer:

there are 52 sundays in a non leap year.

so in a leap year the two extra days(366=364+2)

there are seven  possibilities for the extra day

i.e. the sample space isS={ mon,-tue, tue-wed...sat- sun,sun-mon} (7 possibilities)..n(S)=7

out of which two cases are fav for  the event of having a sunday..n(E)=2

so the prob of there being 53 sundays is

n(E)/n(s)=2/7.

Answered by  | 27th Jul, 2009, 03:38: PM

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