what are some important problems for molality concept
Asked by manoj115860
| 30th Jun, 2017,
01:31: PM
Problems based and asked on all the concepts covered in the chapter are important.
Given below are some important formulae which will help you in solving the problems.
Relative molecular mass of a gas or vapour = 2 × VD
Mole and Gram Atomic Mass: One mole of atoms = 6.022 ×1023 atoms
= Gram atomic mass of an element
= 1 gram atom of the element
Mole and Gram Molecular Mass: One mole of molecules = 6.022 ×1023 molecules
= Gram molecular mass
= 1 gram molecule of the compound
Mole in terms of volume: One mole of a gas = 22.4 litres at S.T.P.
Moles of an element = Mass of the element
Atomic mass or GA.W
Moles of a compound = Mass of the compound
Molecular mass or GMW
Mass of one atom = Atomic Mass or GAW
6.022 × 1023
Mass of one molecule = Molecular Mass or GAW
6.022 × 1023
Number of molecules = Moles × 6.022 ×1023
Number of atoms = Moles × 6.022 ×1023
Problems based and asked on all the concepts covered in the chapter are important.
Given below are some important formulae which will help you in solving the problems.
Relative molecular mass of a gas or vapour = 2 × VD
Mole and Gram Atomic Mass: One mole of atoms = 6.022 ×1023 atoms = Gram atomic mass of an element = 1 gram atom of the element
|
|
Mole and Gram Molecular Mass: One mole of molecules = 6.022 ×1023 molecules = Gram molecular mass = 1 gram molecule of the compound
|
|
Mole in terms of volume: One mole of a gas = 22.4 litres at S.T.P.
|
|
Moles of an element = Mass of the element Atomic mass or GA.W
|
Moles of a compound = Mass of the compound Molecular mass or GMW
|
Mass of one atom = Atomic Mass or GAW 6.022 × 1023
|
Mass of one molecule = Molecular Mass or GAW 6.022 × 1023
|
Number of molecules = Moles × 6.022 ×1023
|
Number of atoms = Moles × 6.022 ×1023
|
Answered by Vaibhav Chavan
| 30th Jun, 2017,
02:51: PM
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