we are given that cos theta+cos square theta=1, then find the value of sin theta+sin square theta?
Asked by Rahul Goel
| 11th Sep, 2010,
04:23: PM
Expert Answer:
Let's call the angle A than θ.
cosA + cos2A = 1
cosA + cos2A -1 = 0
cosA = 1- cos2A
cosA = sin2A
The roots of this quadratic equation,
cosA = (-1±√5)/2 = sin2A
sinA = [(-1±√5)/2]1/2
Hence sinA + sin2A = (-1±√5)/2 + [(-1±√5)/2]1/2
regards,
Team,
TopperLearning.
Let's call the angle A than θ.
cosA + cos2A = 1
cosA + cos2A -1 = 0
cosA = 1- cos2A
cosA = sin2A
The roots of this quadratic equation,
cosA = (-1±√5)/2 = sin2A
sinA = [(-1±√5)/2]1/2
Hence sinA + sin2A = (-1±√5)/2 + [(-1±√5)/2]1/2
regards,
Team,
TopperLearning.
Answered by
| 12th Sep, 2010,
09:44: PM
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