water of mass 75g at 100 C is added to ice of mass 20g at -15 C. whatis the resulting temprature

Asked by  | 16th Mar, 2008, 06:13: AM

Expert Answer:

Heat lost by the hot body = heat gain by the cold body

specific heat of water s = 1cal/g/oc

let the resulting temperature is To

Heat lost by the water = m s ΔT

= 75 x 1 x (100 - To)

Heat gained by the ice

1.) from -15 c to 0 c = m x sx ΔT

= 20 x .5 x (0+15) = 150 cal.

2.) in converting into water at 0o c
   = m x L = 20 x 80

1600 cal.

3.) in raising  the temp. of water formed from 0 to   To

m  s (To - 0 )

= 20 x 1 x To

= 20To

from first

75 (100 - To) = 150 + 1600 + 20 To

 95To = 5750

To =5750/95

=60.5o c

 

Answered by  | 21st May, 2008, 01:57: PM

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