CBSE Class 11-science Answered
water of mass 75g at 100 C is added to ice of mass 20g at -15 C. whatis the resulting temprature
Asked by | 16 Mar, 2008, 06:13: AM
Expert Answer
Heat lost by the hot body = heat gain by the cold body
specific heat of water s = 1cal/g/oc
let the resulting temperature is To
Heat lost by the water = m s ΔT
= 75 x 1 x (100 - To)
Heat gained by the ice
1.) from -15 c to 0 c = m x sx ΔT
= 20 x .5 x (0+15) = 150 cal.
2.) in converting into water at 0o c
= m x L = 20 x 80
1600 cal.
3.) in raising the temp. of water formed from 0 to To
m s (To - 0 )
= 20 x 1 x To
= 20To
from first
75 (100 - To) = 150 + 1600 + 20 To
95To = 5750
To =5750/95
=60.5o c
Answered by | 21 May, 2008, 01:57: PM
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