watching from the top of building 40m high the angle of depression of a moving car increases from 30 angle to 45degree in some internal time find the distance covered by the car in that interval of time.

Asked by Manisha Vadagave | 19th Dec, 2012, 04:35: PM

Expert Answer:

 
AB = building = 40 m
Required distance travelled by the car = CD
 
In triangle ABC,
tan 45 = AB/BC
1 = 40/y
y = 40
 
 
In triangle ABD,
tan 30 = AB/x+y
1/root3 = 40/40+x
x=40(root 3 - 1)

Answered by  | 20th Dec, 2012, 10:29: AM

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