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Volume occupied by a mixture of 64 g SO2 and 64 g CH4 at 1 atm pressure and 0°C is?
Asked by myindiaisbad | 25 Dec, 2022, 02:43: AM
answered-by-expert Expert Answer
Dear Student,
0ºC and 1 atom pressure mens STP.
 
64 gm of sulphur dioxide is equal to 1 mole, therefore 64 gm of SO2​  occupies 22.4 L at STP.
 
1 moleof CH4 = 16 g 
Hence 64 g of CH4 = 4 moles
Therefore, 4 moles of CH4 can occupy 89.6 L at STP.
Answered by | 25 Dec, 2022, 18:17: PM

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