Volume occupied by 10 molecules of water vapour at STP is

Asked by arushidabhade | 13th Aug, 2019, 01:03: PM

Expert Answer:

Density of water = 1000 g/L.

Molecular mass of water = 18.02.

So, number of moles in 1 litre equals fraction numerator 1000 over denominator 18.02 end fraction

                                             = 55.5 moles.

1 mole of water = 6.022 x 1023 molecules of water,

So 55.5 moles of water = 55.5 x 6.022 x 1023 

                                  = 3.34 x 1025 molecules of water.

3.34 x 1025 molecules of water = 1 L,

1 molecules of water = fraction numerator 1 over denominator 3.34 cross times 10 to the power of 25 end fraction

                                = 2.99.0 x 10–24 L.

10 molecules of water will be  2.99 x 10–24 ×10

                                          = 2.99 x 10–23 L

Answered by Varsha | 13th Aug, 2019, 03:22: PM