CBSE Class 9 Answered
Very Urgent
Asked by monicasyal | 31 Jan, 2010, 10:12: PM
Expert Answer
Given: Two circles with centre A and B intersect each other at point P and Q.
PQ is the common chord to the circles.
To Prove: AB is the perpendicular bisector of a common chord
Proof: We know that the line from the centre is perpendicular bisector of the chord.
The line BL passing from centre B, BLP = 90o .................(1)
PL = PQ. ......................(2)
The line AL passing from centre A, ALP = 90o .............(3)
Now, BLP + ALP = 180o (From (1) and (3))
i.e AB is staright line with L as a point on it.
From (1), (2) and (3)
The line AB is a perpendicular bisector of the common chord PQ
Answered by | 01 Feb, 2010, 10:44: AM
Application Videos
Concept Videos
CBSE 9 - Maths
Asked by indu.suresh1220 | 27 Dec, 2023, 11:12: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by subbusuchi1978 | 05 Nov, 2023, 10:24: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by rameshsonkar1234ramesh | 21 Dec, 2022, 11:03: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by sdmbotch1123 | 17 Dec, 2022, 09:39: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by geetaradha8835 | 16 Dec, 2022, 07:59: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by chalkekalyani80 | 06 Mar, 2022, 11:25: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by sangeetabharti123456789 | 22 Feb, 2022, 09:01: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by manognareddy.p28 | 25 Jul, 2021, 12:52: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Samidhaindulkar133 | 11 Mar, 2021, 04:03: PM
ANSWERED BY EXPERT