CBSE Class 11-science Answered
Dear Student
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We have t 0 use 0,1,2,3 at least once in the six digit number.
So first we have to choose 4 places among 6 to put these 4 digits (0, 1, 2, 3).This can be done in 6P4ways. 6P4= 6!/(6-4)! = 6X5X4X3X2X1 / 2X1 = 360 (“! “Denotes factorial)
There are 2 more places left in the six digit number, since there is no restriction on re use of 0, 1, 2, 3 we can choose the remaining 2 digits from ten digits (0, 1, 2, 3, 4, 5, 6, 7, 8, 9) there are 10P2 ways to do this.
10P2=10! / (10-2)! = 90
Total number of all six digit numbers = 360X90=324000
We should not consider the number s starting with “0” as six digit number.
If “0” at the first position there are 5 more digits remained in the six digit number. Those 5 digits can be arranged in 5! Ways, i.e. 150.
324000-150=323850
So total number of six digit numbers is 323850.
Regards
Team
Topper learning