Velocity of a particle moving in a plane is given by v=( 4i +2t^2j) m/s. Avg. Acceleration of particle for time interval between t=0 to t=2 is

Asked by arushidabhade | 21st Jul, 2019, 07:56: PM

Expert Answer:

Velocity vector, v =  ( 4 i + 2t2 j ) m/s
 
at t=0, initial velocity vi = ( 4 i ) m/s
 
at t=2, final velocity  vf  = ( 4 i + 8 j ) m/s
 
average acceleration,  ( vf - vi )/2  = ( 8 j ) / 2 = ( 4 j ) m/s

Answered by Thiyagarajan K | 21st Jul, 2019, 09:31: PM

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