velocity of 3 particles on different axis for colinear position
Asked by jkchandira1277 | 13th Feb, 2010, 10:01: PM
Dear Student
After a time t
position of particle 1= (u1t,0)
position of particle 2= (0, u2t)
position of particle 3= ( ut cos(45),-ut sin(45) )
Say a line joining these points
Y=mx+c;
m=-u2t/u1t
Substitute m in the line eqn
c=y-mx
to get C use point 1
c=0-(-u2t/u1t)u1t=u2t
point 3 must satisfy the line equation to be on the line.
-ut sin(45)=(-u2t/u1t)ut cos(45)+u2t [ sin(45)= cos(45)=1/sqrt2]
(ut/sqrt2)[-1+(u2t/u1t)]=u2t
(ut/sqrt2)= u2t / [-1+(u2t/u1t)]
u= (u2t / [-1+(u2t/u1t)]}t sqrt2
u=t^2 sqrt2 u1u2/(u1-u2)
Regars
Team
Topperlearning.com
Answered by | 15th Feb, 2010, 06:54: PM
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