Asked by | 1st Jun, 2009, 10:35: PM
Let A be the original position of the girl.
Let C be to the north of B So
angle CBA=90 degrees
She travels 30 degrees east of North, so she moves at 30 degrees to BC.
Her position after 3 Km is D say.
angle DBA=60 degrees
Drop perpendicular from D onto AB meeting it at E say.
now, use pythagoras' thm for triangle AED, to find AD which is the required distance
Answered by | 9th Jun, 2009, 08:18: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number