Vectors

Asked by  | 12th Mar, 2010, 10:16: PM

Expert Answer:

Dear Student

a  X(a Xc)+  b =0

==> a  X(a Xc)= - b

ax ac sin theta =-b

Here  by defenition of vector cross product  a is per pendicualr

a^2c sin theta= -b

2sintheta=-1

Sin theta= -1/2

Theta=-30

So the angle is pi/6

Regards

Team

Topperlearning.com

Answered by  | 13th Mar, 2010, 05:59: PM

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