Vectors

Dear Student

a  X(a Xc)+  b =0

==> a  X(a Xc)= - b

ax ac sin theta =-b

Here  by defenition of vector cross product  a is per pendicualr

a^2c sin theta= -b

2sintheta=-1

Sin theta= -1/2

Theta=-30

So the angle is pi/6

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Team

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