CBSE Class 11-science Answered

PCl₅: sp³d hybridization having triagonal bipyramid shape with five 3sp³ d-3p bonds.

The valence electrons in PCl₅ = 5 + 5 × 7 = 40. The distribution of these electrons in PCl₅ is as follows.

There are five lone pairs of electrons around P. Hence, the arrangement of these electrons around P will be triagonal bipyramid, The hybridization involved in this complex is sp³d.

Hence the shape of PCl₅ is:

BrF₅: sp³d² hybradization having octahedral shape with one position occupied by lone pair (or square pyramidal) with five 4sp³d²-2p bonds.

The valance electrons in BrF₅ = 7 + 5 × 7 = 42. The distribution of these electrons in BrF₅ is as follows.

There are six lone pairs of electrons around Br. Hence, the arrangement of these electrons around Br will be octahedral; The hybridization involved in this complex is sp³d².

Hence the shape BrF₅ is: