using the quadratic formula solve: x(square)-4ax+4a(square)-b(square)
Asked by Harshita Bhola | 12th Nov, 2010, 12:00: AM
Expert Answer:
Dear Student,
The quadratic formula says that:
If there is a quadratic equation rx2 + px + q; then
x = [-p ± √(p2 – 4rq)]/(2r)
Hence,
x2 + 4ax + 4a2 – b
=> x = [-4a ± √{(4a)2 – 4 × 1 × (4a2 – b)}]/2
=> x = [-4a ± 2√b]/2
=> x = -2a ± √b
Regards Topperlearning.
Dear Student,
The quadratic formula says that:
If there is a quadratic equation rx2 + px + q; then
x = [-p ± √(p2 – 4rq)]/(2r)
Hence,
x2 + 4ax + 4a2 – b
=> x = [-4a ± √{(4a)2 – 4 × 1 × (4a2 – b)}]/2
=> x = [-4a ± 2√b]/2
=> x = -2a ± √b
Regards Topperlearning.
Answered by | 14th Nov, 2010, 03:55: PM
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