Using Division Lemma.
Asked by vt2008 | 15th Jun, 2009, 01:12: PM
using euclid's division lemma
a= bq+r where r is greater or equal to zero and less than b
so the possible values of r will be 0, 1, 2
so possible values of r are 0, 1and 2.
Now consider consider 3n,3n+1, 3n+2.
cubes are 27n^3, 27n^3+27n^2+9n+1, 27n^3+54n^2+36n+8
i.e 27n^3, 9(3n^3+3n^2+n)+1, 9(3n^3+6n^2+4n)+8
which all have the form 9m,9m+1 or 9m+8
Answered by | 15th Jun, 2009, 02:32: PM
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