CBSE Class 10 Answered
use euclid's algorithm to find hcf of 1190 and 1445. express the hcf in the form 1190m+1445n
Asked by arvindgarg.obc | 28 Feb, 2018, 10:42: AM
Expert Answer
1445=1190 x 1 + 255
1190=255 x 4 +170
255=170 x 1 + 85
170=85 x 2 + 0
HCF = 85
Now,
85 = 255 - 170
=(1445-1190)-(1190-255 x 4)
=1445-1190-1190+255 x 4
=1445-1190 x 2+(1445-1190) x 4
=1445-1190 x 2+1445 x 4-1190 x 4
=1445 x 5 - 1190 x 6
=1190 x (-6) + 1445 x 5
=1190m + 1445n, where m= -6 and n = 5
(-By Prabal)
Answered by Sneha shidid | 28 Feb, 2018, 11:36: AM
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