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use euclid's algorithm to find hcf of 1190 and 1445. express the hcf in the form 1190m+1445n
Asked by arvindgarg.obc | 28 Feb, 2018, 10:42: AM Expert Answer

1445=1190 x 1 + 255

1190=255 x 4 +170

255=170 x 1 + 85

170=85 x 2 + 0

HCF = 85

Now,

85 = 255 - 170

=(1445-1190)-(1190-255 x 4)

=1445-1190-1190+255 x 4

=1445-1190 x 2+(1445-1190) x 4

=1445-1190 x 2+1445 x 4-1190 x 4

=1445 x 5 - 1190 x 6

=1190 x (-6) + 1445 x 5

=1190m + 1445n, where m= -6 and n = 5

(-By Prabal)

Answered by Sneha shidid | 28 Feb, 2018, 11:36: AM
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