CBSE Class 9 Answered
urgent......
Asked by vsprasanthi | 01 Mar, 2010, 07:23: AM
Expert Answer
let AB,CD be the intersecting chords intersecting at E.
P be the point of intersection and O be the center of the circle, obviously O lies on the diameter.
draw OL and OM perpendiculars to AB,CD respectively.
in triangles LOP,MOP,
we have
angle LPO=angle MPO.... given
angle OMP= angle OLP.. each 90 degrees because of construction
OP=OP....common
so triangles become congruent
so
OL=OM... CPCT
thus we can say,
distance of AB from the center = dist of CD from the center
so
AB=CD
chords which are equidistant from the center are equal in length.
Answered by | 01 Mar, 2010, 07:08: PM
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