Asked by vsprasanthi | 1st Mar, 2010, 07:23: AM
let AB,CD be the intersecting chords intersecting at E.
P be the point of intersection and O be the center of the circle, obviously O lies on the diameter.
draw OL and OM perpendiculars to AB,CD respectively.
in triangles LOP,MOP,
angle LPO=angle MPO.... given
angle OMP= angle OLP.. each 90 degrees because of construction
so triangles become congruent
thus we can say,
distance of AB from the center = dist of CD from the center
chords which are equidistant from the center are equal in length.
Answered by | 1st Mar, 2010, 07:08: PM
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