urgent

Asked by pritam | 31st Aug, 2010, 12:10: PM

Expert Answer:

We know that
sec2A-tan2A=1 and cosec2A-cot2=1
multiply the Nr and Dr of LHS by secA-tanA
so we get,
LHS
=[(secA+tanA)(secA-tanA)]/[(cosecA+cotA)(secA-tanA)]
=1/[(cosecA+cotA)(secA-tanA)]
now multiply the Nr and Dr by cosecA-cotA
so
LHS
=(cosecA-cotA)/(secA-tanA)
RHS.

Answered by  | 31st Aug, 2010, 04:05: PM

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