Asked by srprusty | 16th Mar, 2009, 10:38: PM
Let the dimensions be l and b ( length and breadth).
Acc to qn,
clearly if l and b are both zero, then rectangle doen' exist actually.
So next possible value for l must be >2
As the denominator has l-2, which must be positive.
Also, since lb=2(l+b),
so clearly lb is an even number.
So both l and b can't be odd numbers.
by giving values to l, you can gt b
and thus the dimensions.
Answered by | 16th Mar, 2009, 11:10: PM
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