Asked by pritam | 6th Apr, 2010, 10:28: PM
u = -5 m
f = R/2 = +20/2 = 10 m
Therefore, 1/v + 1/u = 1/f
ie, 1/v = 1/f - 1/u
= (1/10) - (1/-5)
= (1/10) + (1/5)
thus, v = +10/3 m.
= 3.333 m.
Magnification, h'/h = -v/u = -[10/(3x-5)] = +2/3
The image is formed betweent the pole and the focus.
Nature of the image is Virtual and Erect.
Image formed is diminished by a factor of 2/3.
Answered by | 8th Apr, 2010, 10:48: AM
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