Urgent!!
Asked by RACHIT_MAHAAN
| 15th Feb, 2010,
05:57: PM
Expert Answer:
x2 - P(x+1) - C = 0
x2 - Px - P - C = 0
Comparing with the standard quadratic equation in terms of roots A and B, x2- (A+B)x + AB = 0, we find,
A+B = P and AB = -P-C
(A+1)(B+1) = 0
AB + A+B + 1 = 0
-P - C + P + 1 = 0
C = 1.
Regards,
Team,
TopperLearning.
Answered by
| 16th Feb, 2010,
06:23: AM
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