Urgent!!

Asked by RACHIT_MAHAAN | 15th Feb, 2010, 05:57: PM

Expert Answer:

x2 - P(x+1) - C = 0

x2 - Px - P - C = 0

Comparing with the standard quadratic equation in terms of roots A and B, x2- (A+B)x + AB = 0, we find,

A+B = P and AB = -P-C

(A+1)(B+1) = 0

AB + A+B + 1 = 0

-P - C + P + 1 = 0

C = 1.

Regards,

Team,

TopperLearning.

Answered by  | 16th Feb, 2010, 06:23: AM

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