urgent

Asked by pritam | 31st Aug, 2010, 11:52: AM

Expert Answer:

(sin2A)3+(cos2A)3
=
(sin2A+cos2A)[sin4A-sin2Acos2A+cos4A].... using formula for a3+b3=a2-ab+b2
=(1)[(sin2A+cos2A)2-2sin2Acos2A-sin2Acos2A]
=RHS

Answered by  | 31st Aug, 2010, 04:47: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.