urgent
Asked by pritam
| 31st Aug, 2010,
11:52: AM
Expert Answer:
(sin2A)3+(cos2A)3
=
(sin2A+cos2A)[sin4A-sin2Acos2A+cos4A].... using formula for a3+b3=a2-ab+b2
=(1)[(sin2A+cos2A)2-2sin2Acos2A-sin2Acos2A]
=RHS
Answered by
| 31st Aug, 2010,
04:47: PM
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