UNKNOWN VALUES
Asked by RACHIT_MAHAAN | 19th Sep, 2010, 02:39: PM
Expert Answer:
[tan(A+B) + tan(A-B)]/(1 - tan(A+B)tan(A-B)) = tan (A+B+A-B) = tan 2A
(m + n)/(1 - mn) = tan 2A.
Similarly,
[tan(A+B) - tan(A-B)]/(1 + tan(A+B)tan(A-B)) = tan (A+B-(A-B)) = tan 2B
(m - n)/(1 + mn) = tan 2B.
regards,
Team,
TopperLearning.
[tan(A+B) - tan(A-B)]/(1 + tan(A+B)tan(A-B)) = tan (A+B-(A-B)) = tan 2B
(m - n)/(1 + mn) = tan 2B.
regards,
Team,
TopperLearning.
Answered by | 19th Sep, 2010, 03:14: PM
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