Under the same conditions of temperature and pressure samples of gases- H2, O2, N2, and CO2- contain the same number of molecules represented by N. If the molecules of H2 occupies V litres and has a mass of 2 gm. then:

i) calculate the volume occupied by- 1) N molecules of CO2;

2) 3N mlecules of O2;

3)N/2 moleules of O2.

Asked by bdroy_2014 | 28th Jan, 2018, 03:07: PM

Expert Answer:

Mass space of space straight H subscript 2 space equals space 2 space gm

1 space mole space of space straight H subscript 2 space equals space 2 space gm space
space space space space space
space space space space space space space space space space space space space space space space space space space space space space equals space 6.023 cross times 10 to the power of 23 space molecules space of space straight H subscript 2

space space space space space space space space space space space space space space space space therefore space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules

As space Under space the space same space conditions space of space temperature space and space pressure space samples space of space gases space straight H subscript 2 comma space straight O subscript 2 comma space straight N subscript 2 comma space and space CO subscript 2
space contain space the space same space number space of space molecules
open parentheses 1 close parentheses
therefore space volume space occupied space by space straight N space molecules space of space CO subscript 2

space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules

space space space space space equals space 1 space mole
space space space space space
space space space space space space equals space 22.4 space lit
space space space space space
space volume space occupied space by space straight N space molecules space of space CO subscript 2 space equals space 22.4 space lit

open parentheses 2 close parentheses

space Volume space occupied space by space 3 straight N space molecules space of space straight O subscript 2
space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules

3 straight N equals space 3 cross times space space 6.023 cross times 10 to the power of 23 space molecules

space space space space space space equals space 3 cross times 22.4
space space space space space
space space space space space space equals space 67.2 space lit
space Volume space occupied space by space 3 straight N space molecules space of space straight O subscript 2 space equals space space 67.2 space lit

open parentheses 3 close parentheses

space Volume space occupied space by space straight N divided by 2 space space molecules space of space straight O subscript 2

space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules

straight N over 2 equals space fraction numerator space 6.023 cross times 10 to the power of 23 over denominator 2 end fraction
space space
space space space space space equals space fraction numerator 22.4 over denominator 2 end fraction

space space space space space space equals space 11.2 space lit

Volume space occupied space by space straight N divided by 2 space space molecules space of space straight O subscript 2 space space equals space 11.2 space lit

Answered by Varsha | 29th Jan, 2018, 02:51: PM