Two years ago, Jacob's age was three times the square of John's age. In three years time, John's age will be one-fourth of Jacob's age. Find their present ages.
Asked by pinkle | 24th Oct, 2010, 12:52: PM
Assume the Jacobs and Johns age to be x and y respectively.
According to the first condition,
(x-2) = 3(y-2)2 .....(1)
According to the second condition,
(y+3) = (x+3) ....(2)
Now from second equation find the value of any one veriable in terms of other and substitute in equation one to get the required quadratic equation.
Topper Learning Team
Answered by | 25th Oct, 2010, 09:34: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number