TWO VESSELS 'A' AND 'B' CONTAIN A MIXTURE OF SPIRIT AND WATER. A MIXTURE OF 3 PARTS FROM 'A' AND 2 PARTS FROM 'B'IS FOUND TO CONTAIN 29% OF SPIRIT AND A MIXTURE OF 1PART FROM 'A' AND 9 PARTS FROM 'B' IS FOUND TO CONTAIN 34% OF SPIRIT. FIND THE PERCENTAGES OF SPIRIT CIN 'A' AND'B'

Asked by  | 14th Apr, 2013, 11:08: AM

Expert Answer:

Let A contain x% spirit and B contain y% spirit
 
Hence, (3x + 2y)/5 = 29
Hence, 3x + 2y = 145    (1)
 
Also, (x+9y)/10 = 34
x+9y = 340
3x+27y = 1020    (2)
 
Subtracting 1 from 2
 
25y = 875
y = 35%
 
x = 340-315 = 25%

Answered by  | 14th Apr, 2013, 05:51: PM

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