two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of

Asked by  | 26th Aug, 2009, 05:33: PM

Expert Answer:

Let x be the original distance between them,

so the total distance travelled by the second train is this original distance plus the length of the first train plus it's own length since the guard of second train B just brushes past the driver of A.

= x + 800

Net displacement = x + 800

Initial relative velocity = 72 - 72 = 0,

acceleration = 1m/s2,

time = 50 s,

Using the kinematic equation,

s = ut + at2/2,

x + 800 = 1(50)2/2

x = the original separation distance between the trains = 450 m.




Answered by  | 26th Aug, 2009, 09:59: PM

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