two tall building are 200 m apath with what must a ball will throw horizontally from window 540 m above the ground in building so as to enter a 50 m high window in the other building 
(hint:find speed)

Asked by Manisha Marwaha | 25th Jun, 2014, 11:57: PM

Expert Answer:

Given that the distance between the two buildings , x = 200 m.

Consider the motion along the vertical :

we need to find the time needed for the the ball to cover the vertical separation between the two buiding, y = 540 m - 50 m = 490 m .

Initial velocity uy=0 , y =490 m, ay = g =9.8 m/s2

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Now, the distance between the two buildings , x = 200 m.

Therefore the speed with which the ball must be thrown can be determined by :

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Therefore the speed with which the ball must be thrown horizontally from window 540 m above the ground of one building to enter a 50 m high window in the other building is 20 m/s

Answered by Jyothi Nair | 26th Jun, 2014, 09:12: AM