Two simple pendulums of length 1m and 16 m respectively are both given a small displacement in same direction at the same instant.They will be again in phase after the shorter pendulum has completed "n " oscillations.Calculate "n".

Asked by  | 7th Feb, 2012, 09:23: PM

Expert Answer:

LET the time periods of two pendulums are T1 and T2 .
From the questio T1=T2/4.
so when first pendulum will complete its four oscillations the bigger one will complete its one oscillation. So they will be in phase for n=4

Answered by  | 8th Feb, 2012, 11:56: AM

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