Two questions on Permutation.

Dear Student

Please ask only one question per query

Solution to your First question is as follows:

Mixed double will involve 4 people 2 men and 2 women

 

select unique groups of 4 people two men can be selected from 7 and women can be selected from remaining 5 (excluding their wifes)

⁷C₂ X ⁵C₂ = 210

 

i.e there are 210 unique combinations of the 4 people

Multiply the resultant with 2 (i.e for every unique combination of 4 people there are 2 teams possible)


so nos of teams = 2x210

=420
 



Hope it clarifies your doubt

Regards

Team Topperlearning