Two point charges q1=+9microcoulomb and q2=-1microcoulomb are held 10 cm apart. Where should at third charge +Q be placed from q2 on the line joining them so that charge Q does not experience any net force?

Asked by Rishabh Nehra | 9th May, 2012, 04:44: PM

Expert Answer:

fore on Q due to q1=force on Q due to q2
kq1Q/(10-x)2 =kq2Q/x2
after solving the above equation, x=2.5 cm

Answered by  | 9th May, 2012, 05:45: PM

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